So, a spherical surface is the set of all points in space that are at a fixed distance (radius, usually denoted by ) from a given point (center, ).
In this tutorial, we'll learn how to find the surface area of a sphere. And given how often we see the spherical shape around us, I am sure we all have some intuitive understanding of what a sphere is.
So, a spherical surface is the set of all points in space that are at a fixed distance (radius, usually denoted by ) from a given point (center, ).
It’s very similar to the concept of a circle. The key difference is – a circle is the set of all points in a plane (instead of space) that are equidistant from a given point.
Unlike a cone, cube, or cylinder, a sphere does not have any edges. So a sphere has only one continuous surface. And the area covered by this surface is the surface area of the sphere.
For a sphere with a radius , the surface area is given by
Archimedes, the famous Greek polymath, found that the surface area of a sphere is equal to the curved surface area of a cylinder with a radius equal to the sphere's radius and height equal to the sphere's diameter.
Now, the curved surface area of a cylinder is given by –
Replacing with radius and height is given by
Hence the curved surface area of a sphere must be equal to
Alright. Time to solve a few examples using what we have learned so far.
Find the surface area of a sphere with a diameter of inches.
Solution
The surface area of a sphere is given by -
But the question doesn't give us the radius. Instead, it tells us the diameter is inches. So first we need to get the radius.
Now, substituting the value of the radius into our formula for area, we have
So the surface area of the sphere is .
What is the radius of a sphere that has a surface area of ?
Solution
Again, the surface area of a sphere is given by –
And the question tells us that the area is . So,
Solving for , we get
That's it.
And with that we come to the end of this tutorial. Until next time.
We use cookies to provide and improve our services. By using the site you agree to our use of cookies. Learn more